3.10-3.11 Lists and Searches
Basic Operations
#Defining the List
aList= [1,4,2,6,7,3,]
# Accessing Elements in a list
print(aList[1])
#Storing Element at an Index to a variable
Element = aList[3]
print(Element)
#Setting an Element at an Index to a variable
element = 4
aList[5]= element
print(aList[5])
#Insert a value at a certain index
aList.insert(3, 10)
print(aList[3])
#Adding another value to the list (append)
aList.append(5)
print(aList)
#Removing a value from the List at a specific Index
aList.remove(2)
print(aList)
#Accessing the Length of a list
print(len(aList))
4
6
4
10
[1, 4, 2, 10, 6, 7, 4, 5]
[1, 4, 10, 6, 7, 4, 5]
7
PopCorn hack #1
- Create and define your own list and insert a value at a certain index
#Enter code here
Finding the Minimum Value in a List
nums = [30, 45, 95, 56, 73, 98, 25]
min_value = nums[4] # Start with the first element as the minimum
for score in nums:
if score < min_value:
min_value = score
print(min_value) # Display the minimum value
25
PopCorn hack #2
- Using the code above try to find the maximum value in the list
#Enter Code here
Sum of Even Numbers in a list solution
#Defining numbers in list
nums = [7, 5, 10, 6, 9, 4, 3, 12]
sum_even = sum([score for score in nums if score % 2 == 0]) #Using for loop to work through each number in the list and using mod to interpret if any numbers have a remainder of 0
print(sum_even)
32
Determining Outputs for code Segments with Length function
#Defining the list
words = ['old', 'computer', 'science', 'far', 'potato']
new_words = []
for word in words:
if len(word) != 3: #if the length of the word is not equal to three
new_words.append(word) #adds it to a new list if the length is not equal to three
print(new_words)
['computer', 'science', 'potato']
If Else Statements with Lists
Performing a Binary Search
- index: organizing the data by assigning a reference value to each element
- Put the number is order either ascending or descending
- Search starts with middle number first which is found by adding the highest and lowest index number and dividing it by 2
- This divides the range by 2
- Repeat this process by shrinking the range each time till the desired target is found
- Every time the process is repeated and leads to a target it is considered a comparison
Performing a Sequential Search
- Each element in a list is examined in the order of the first element till the desired target
- Order doesn’t matter
Homework Hack 1
- What will be the middle index number in a Binary Search given the set of number: 3, 6, 12, 14, 50, 53
- Which of the following lists can a Binary Search be used to find the desired target
- This is a multiple choice question
fruits= ['Apple', 'Carrot', 'Mango', 'Peach']
A= [1, 3, 5, 8, 9, ]
B= [6, -1, 5, 12, 8]
#Type your choices below
Homework Hack 2
- Given a provided list perform two of the basic operations
yourlist = [8,10,35,39,49,52]
#type out your answers below and run the code and include output in screenshot
Reflection:
Tne learning from trimester 1 was watching the college board videos and understanding the basis and foundations of sequential searches and how it is implemented into most projects